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Better fix for not using the unsafe to break flag

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Recognize special glyphs by comparing the index to the glyph for the
codepoint in the font. Cannot rely on glyph width as many glyphs have
zero width. For example the glyph for space characters.
This commit is contained in:
Kovid Goyal
2017-11-13 07:03:58 +05:30
parent 339c0d2980
commit 9fccc38382
3 changed files with 68 additions and 32 deletions
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4
kitty_tests/fonts.py
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@@ -81,6 +81,10 @@ class Rendering(BaseTest):
self.ae(groups('abcd'), [(1, 1) for i in range(4)])
self.ae(groups('A=>>B!=C', path='kitty_tests/FiraCode-Medium.otf'), [(1, 1), (3, 3), (1, 1), (2, 2), (1, 1)])
colon_glyph = shape_string('9:30', path='kitty_tests/FiraCode-Medium.otf')[1][2]
self.assertNotEqual(colon_glyph, shape_string(':', path='kitty_tests/FiraCode-Medium.otf')[0][2])
self.ae(colon_glyph, 998)
self.ae(groups('9:30', path='kitty_tests/FiraCode-Medium.otf'), [(1, 1), (1, 1), (1, 1), (1, 1)])
self.ae(groups('|\U0001F601|\U0001F64f|\U0001F63a|'), [(1, 1), (2, 1), (1, 1), (2, 1), (1, 1), (2, 1), (1, 1)])
self.ae(groups('He\u0347\u0305llo\u0337,', path='kitty_tests/LiberationMono-Regular.ttf'),
[(1, 1), (1, 3), (1, 1), (1, 1), (1, 2), (1, 1)])